Vektor – 5 die Lage zwischen zwei Geraden
Man zeige, dass die Gerade h durch die Punkte A und B und |
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die gerade k durch C und D sich in einem Punkt S schneiden. |
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Man bestimme den Winkel zwischen h und k. |
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Ergebnisse |
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A |
1,0 |
3,0 |
2,0 |
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1,0 |
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1,0 |
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r= 1,00 |
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g(AB): |
X = |
3,0 |
+ r |
5,0 |
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s= 1,00 |
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B |
2,0 |
8,0 |
5,0 |
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2,0 |
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3,0 |
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C |
8,0 |
13,0 |
6,0 |
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8,0 |
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-6,0 |
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S |
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8 |
5) |
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g(CD): |
X = |
13,0 |
+ s |
-5,0 |
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D |
2,0 |
8,0 |
5,0 |
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6,0 |
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-1,0 |
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α= |
136,9 ° |
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Ergebnisse |
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A |
2,0 |
8,0 |
5,0 |
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2,0 |
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7,0 |
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r =1,00 |
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g(AB): |
X = |
8,0 |
+ r |
10,0 |
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s =0,50 |
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B |
9,0 |
18,0 |
9,0 |
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5,0 |
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4,0 |
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C |
15,0 |
23,0 |
10,0 |
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15,0 |
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-12,0 |
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S |
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18 |
9) |
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g(CD): |
X = |
23,0 |
+ s |
-10,0 |
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D |
3,0 |
13,0 |
8,0 |
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10,0 |
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-2,0 |
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α= |
161,6 ° |
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Ergebnisse |
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A |
1,0 |
5,0 |
3,0 |
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1,0 |
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6,0 |
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r =1,00 |
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g(AB): |
X = |
5,0 |
+ r |
5,0 |
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s =0,33 |
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B |
7,0 |
10,0 |
4,0 |
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3,0 |
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1,0 |
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C |
8,0 |
15,0 |
7,0 |
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8,0 |
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-3,0 |
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S |
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10 |
4) |
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g(CD): |
X = |
15,0 |
+ s |
-15,0 |
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D |
5,0 |
0,0 |
-2,0 |
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7,0 |
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-9,0 |
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α= |
136,9 ° |
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Ergebnisse |
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A |
-1,0 |
-5,0 |
-3,0 |
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-1,0 |
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-6,0 |
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r =1,00 |
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g(AB): |
X = |
-5,0 |
+ r |
-5,0 |
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s =0,25 |
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B |
-7,0 |
-10,0 |
-4,0 |
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-3,0 |
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-1,0 |
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C |
-6,0 |
-5,0 |
-1,0 |
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-6,0 |
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-4,0 |
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S |
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-10 |
-4) |
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g(CD): |
X = |
-5,0 |
+ s |
-20,0 |
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D |
-10,0 |
-25,0 |
-13,0 |
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-1,0 |
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-12,0 |
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α= |
43,1 ° |
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Ergebnisse |
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A |
-7,0 |
-12,0 |
-5,0 |
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-7,0 |
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-11,0 |
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r =1,00 |
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g(AB): |
X = |
-12,0 |
+ r |
-5,0 |
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s =1,00 |
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B |
-18,0 |
-17,0 |
-4,0 |
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-5,0 |
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1,0 |
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C |
-12,0 |
-12,0 |
-3,0 |
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-12,0 |
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-6,0 |
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S |
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-17 |
-4) |
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g(CD): |
X = |
-12,0 |
+ s |
-5,0 |
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D |
-18,0 |
-17,0 |
-4,0 |
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-3,0 |
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-1,0 |
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α= |
19,5 ° |
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Ergebnisse |
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A |
-11,0 |
-7,0 |
0,0 |
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-11,0 |
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1,0 |
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r =1,00 |
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g(AB): |
X = |
-7,0 |
+ r |
5,0 |
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s =0,50 |
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B |
-10,0 |
-2,0 |
3,0 |
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0,0 |
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3,0 |
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C |
-4,0 |
3,0 |
4,0 |
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-4,0 |
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-12,0 |
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S |
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-2 |
3) |
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g(CD): |
X = |
3,0 |
+ s |
-10,0 |
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D |
-16,0 |
-7,0 |
2,0 |
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4,0 |
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-2,0 |
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α= |
136,9 ° |
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Ergebnisse |
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A |
-4,0 |
5,0 |
5,0 |
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-4,0 |
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12,0 |
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r =1,00 |
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g(AB): |
X = |
5,0 |
+ r |
10,0 |
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s =0,25 |
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B |
8,0 |
15,0 |
7,0 |
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5,0 |
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2,0 |
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C |
4,0 |
20,0 |
12,0 |
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4,0 |
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16,0 |
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S |
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15 |
7) |
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g(CD): |
X = |
20,0 |
+ s |
-20,0 |
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D |
20,0 |
0,0 |
-8,0 |
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12,0 |
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-20,0 |
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α= |
95,4 ° |
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Ergebnisse |
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A |
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5,0 |
-1,0 |
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11,0 |
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-6,0 |
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r =1,00 |
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g(AB): |
X = |
5,0 |
+ r |
-5,0 |
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s =2,00 |
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B |
5,0 |
0,0 |
-2,0 |
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-1,0 |
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-1,0 |
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C |
1,0 |
5,0 |
3,0 |
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1,0 |
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2,0 |
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S |
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0 |
-2) |
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g(CD): |
X = |
5,0 |
+ s |
-2,5 |
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D |
3,0 |
2,5 |
0,5 |
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3,0 |
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-2,5 |
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α= |
84,6 ° |
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